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LiRa [457]
3 years ago
5

A set of equations is given below:

Mathematics
1 answer:
artcher [175]3 years ago
7 0

Answer:

comparing both equation we get,

2X+1=X+9

or, X=8

Y=X+9

or, Y=17

therefore the required solution is (8,17)

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What is the width of the rectangle shown below? <br>4x + 3 <br>A = 8x2 – 10x – 12
ozzi

Answer:

<h2><em>2x-4</em></h2>

Step-by-step explanation:

Area of a rectangle = Length * Width

Given parameters

Area A = 8x2 – 10x – 12

Length of the rectangle = 4x+3

Required

Width of the rectangle.

Substituting the given parameters into the formula

8x2 – 10x – 12  = (4x+3)*width

width = 8x2 – 10x – 12 /4x+3

S

Factorizing the numerator

8x² – 10x – 12

= 2(4x²-5x-6)

= 2(4x²-8x+3x-6)

= 2(4x(x-2)+3(x-2))

= 2(4x+3)(x-2)

Width = 2(4x+3)(x-2)/4x+3

Width = 2(x-2)

Width = 2x-4

<em>Hence the width of the rectangle is 2x-4</em>

8 0
3 years ago
Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,
wariber [46]
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
7 0
3 years ago
0.1325 to thr hundredths
viktelen [127]
.13 hope this helps :D
6 0
3 years ago
Read 2 more answers
Please help (10POINTS)
kobusy [5.1K]

Answer: it’s d

Step-by-step explanation: i did that

6 0
3 years ago
HELP WILL GIVE BRAINLIEST!
andriy [413]

Answer:

128 boxes

Step-by-step explanation:

The dimensions of the trunk is 24 in. by 24 in by 48 in

The volume = 24(24)(48) = 27648 cu. in.

The cubed boxes each have a volume of 6(6)(6) = 216 cu. in.

27648/216 = 128 boxes

8 0
3 years ago
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