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2 years ago

A set of equations is given below:

Mathematics

1 answer:

artcher [175]2 years ago

7 0

Answer:

comparing both equation we get,

2X+1=X+9

or, X=8

Y=X+9

or, Y=17

therefore the required solution is (8,17)

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Len [333]

Answer:

In the operation, simplify

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4a²-4a-24-------------------divide each term by 4

a²-a-6-------------------------factorize

a²-3a+2a-6

a(a-3)+2(a-3)

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Rewrite operation as

$\frac{8}{(3-a)(3+a)} /\frac{(a+2)(a-3)}{(a-3)(a-3)}$

Multiply by the recipricol

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cancel the similar terms

$\frac{8}{(3-a)(3+a)} *\frac{(a-3)}{(a+2)}$

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2 years ago