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Katena32 [7]
3 years ago
5

Hey, can someone help me with my math homework?

Mathematics
1 answer:
Stels [109]3 years ago
7 0

aqueell ears hanan pus

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The figures below are similar. the area of the larger trapezoid is 121m^2. Find the area of the smaller trapezoid to the nearest
DENIUS [597]

Answer:

54 square meters

Step-by-step explanation:

Similar figures have corresponding lengths as equal ratios.

Smaller trapezoid's base is given 12 and larger trapezoids base is given 18, so the scale factor is 12k=18\\k=\frac{18}{12}\\k=1.5

<em>this means the lengths of larger is 1.5 times lengths of smaller.</em>

<em />

In terms of area, the scale factor is squared. Hence the scale factor for area is  k^2=(1.5)^2=2.25

<em>this means the area of larger is 2.25 times the area of smaller.</em>

<em />

Now, Let area of smaller trapezoid be x so we can say:  x(2.25)=121\\x=\frac{121}{2.25}\\x=53.78

<em>to nearest square meter, </em><em>x = 54 meters squared</em>

6 0
3 years ago
Linda and Carrie made a trip from their hometown to a city about 200 miles away to attend a friend's wedding. The following char
marissa [1.9K]
The correct answer is C) 58/73.

We first add up the amount of time spent driving:
3 + 1 1/2 + 20 minutes

Changing 20 minutes to a fraction of an hour, 20/60 = 1/3:
3 + 1 1/2 + 1/3

Using the LCD (6), 
3 + 1 3/6 + 2/6 = 4 5/6 hrs driving.

Now we find the total time of the trip:
3 + 15 min + 1 1/2 + 1 + 20 min
= 3 + 15/60 + 1 1/2 + 1 + 20/60
= 3 + 1/4 + 1 1/2 + 1 + 1/3

The LCD for this is 12:
3 + 3/12 + 1 6/12 + 1 + 4/12 = 5 13/12 = 6 1/12

We find the ratio of driving to total time, which is (4 5/6)/(6 1/12)
= 4 5/6 ÷ 6 1/12

Converting the mixed numbers to improper fractions,

29/6 ÷ 73/12 = 29/6 × 12/73 = 348/438 = 174/219 = 58/73
6 0
3 years ago
Quadrilateral A'B'C'D' is a dilation of quadrilateral ABCD about point P Is this dilation a reduction or an enlargement? O reduc
Mama L [17]

Answer: reduction

Step-by-step explanation:

ABCD-> 'ABCD

its bc 'ABCD got smaller compared to ABCD

4 0
3 years ago
Read 2 more answers
Help solve for “q”<br> —————————————
VMariaS [17]

Digram:-

\\

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}

\\

STEP :-

\dashrightarrow \tt(4q - 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

{Linear pair}

\\  \\

\dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ}   - {117}^{ \circ}

\\

\dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}

\\

\dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}

\\

\dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}

\\

\dashrightarrow \tt4q =64{}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{64}{4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16 \times 4}{4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}

\\

\dashrightarrow \tt \: q =  \dfrac{16}{1}

\\

\dashrightarrow \bf q = 16 \degree

\\  \\

Verification:

\\

\dashrightarrow \tt(4 \times 16- 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt(64- 1) {}^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt63^{ \circ}  +  {117}^{ \circ}  = 18 {0}^{ \circ}

\\

\dashrightarrow \tt180^{ \circ}  = 18 {0}^{ \circ}

\\

LHS = RHS

HENCE VERIFIED!

8 0
3 years ago
How do i graph the lines when the equations aren’t in slope intercept form????
jekas [21]

Slope-Intercept Form: y=mx+b

Standard Form: ax+by=c

Point- Slope: (y-y1)= m(x-x1)

There are multiple answers to your question-

  1. If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
  2. If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
  3. If you are given the standard form/point-slope form, change the equation to slope intercept form.
  4. If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.
7 0
3 years ago
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