Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
9/8 is in the simplest form
Here’s the correct answer and how I got it :)
A negative slope means the line would be going downward, so you would go down first (instead of up as with a positive slope), then over right.
Therefore, you would go down 4 (or negative 4 considering you are going down) and right 1.
Rise over run still applies here. Rise over run is a fancy way of saying to put the number (or slope) in fraction form.
-4 as a fraction would be -4/1.
So start at (5,3), go down 4 and over 1, repeatedly and you got it.
**Just remember the rise over run can be confusing with negative slopes.**
hookes law gives the equation F=kx where F is the elastic force and k is the constant and x or small e is extension if we draw a graph you'll see that the graph increases by the same ratio every single time hence giving a straight line show that they are F and x are propotional to a certain limit