Area = 304 cm^2
perimeter = 70
perimeter = 2(l+w)
70 = 2(l+w)
70/2 = l+w
35 = l+w
Now suppose the length would be = x
width would be= 35-x
NOW Area = l*w
304 = x * (35-x)
304 = 35x -x^2
x^2-35x+304 = 0
use quadratic formula to solve next ok
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For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
Answer: 432cm^3
Step-by-step explanation:
<em>QUESTION:</em>
<em>QUESTION:estimate the equation 12+19.61.</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.</em>
