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Dmitry_Shevchenko [17]
3 years ago
10

Easy and quick! is B the answer to this?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Tems11 [23]3 years ago
3 0
Yes sirr
You are correct
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A square has an area of 25 yd . What is the length of each side? in yd
Lady_Fox [76]

Answer:

The side length is 5 yds

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

25 = s^2

Take the square root of each side

sqrt(25) = sqrt(s^2)

5 = s

The side length is 5 yds

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4 years ago
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Solving basic combined equations <br><br> 5x - 3=22
tensa zangetsu [6.8K]
5x - 3 =22&#10;&#10; add the 3 over. 5x = 25 divide by 5. x = 5
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Dimitrius returned 5 library books last week, returned 3 books this week, and then checked out 8 more books. He now has 12 libra
g100num [7]
To solve this problem, we have to set up an equation. Let the variable x represent the number of books that Dimitrius had before last week. x - 5 - 3 + 8 = 12 To begin simplifying this equation, lets combine terms on the left side of the equation. x - 8 + 8 = 12 The -8 and +8 cancel each other out, leaving us with: x=12 Therefore, Dimitrius had 12 books before last week. Hope this helps! :)
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3 years ago
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Can someone please help
andrey2020 [161]
There’s no question
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3 years ago
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a box with a square base and open top must have a volume of 70304 c m 3 cm3 . we wish to find the dimensions of the box that min
Dmitriy789 [7]

The box should have base 52 cm by 52 cm and height 26 cm.

What is volume?

A three-dimensional space's occupied volume is measured. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.

The Volume of a box with a square base x by x cm and height h cm is

V = x^2h

Since the surface area directly affects the amount of material used, we can reduce the amount of material by reducing the surface area.

The surface area of the box described is  A = x^2 + 4xh

We need A as a function of x alone, so we'll use the fact that

V = x^2h= 70304 cm^3

⇒ h = \frac{70304}{x^2}

So, the area becomes,

A = x^2+4x(\frac{70304}{x^2})\\ A = x^2 + \frac{281216}{x}

We want to minimize A, so

A' = 2x - \frac{281216}{x^2} =0\\\frac{2x^3-281216}{x^2}=0\\ {2x^3-281216} = 0\\x^3 - 140608=0\\x^3 = 140608\\x = 52

The second derivative test verifies that A has a minimum at this critical number:

A'' = 2+\frac{562432}{x^3}  which is positive at x = 52.

Now,

h = \frac{70304}{x^2}= \frac{70304}{(52)^2}=26

Hence, The box should have base 52 cm by 52 cm and height 26 cm.

To know more about volume, click on the link

brainly.com/question/463363

#SPJ4

8 0
2 years ago
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