All categories

2 years ago

I need help with this rq

Mathematics

2 answers:

Vesnalui [34]2 years ago

7 0

Answer:

228.4

Step-by-step explanation:

9.2 + 9.2 + 60 + 75 +75 which is 228.4. Remember to divide the triangles by two after you do base times height.

SVETLANKA909090 [29]2 years ago

5 0

Answer and Step-by-step explanation:

To find the surface area, we find the area of all the shapes in the prism, then add them together.

Triangles:

(4 × 4.6) ÷ 2 = 18.4 ÷ 2 = 9.2

Rectangle 1:

4 × 15 = 60

Rectangle 2 and 3:

5 × 15 = 75

9.2 + 9.2 + 60 + 75 + 75 = 228.4

228.4 is the total surface area.

#teamtrees #PAW (Plant And Water)

You might be interested in

What is the equation of a circle whose center is begin ordered pair negative 4 comma 6 end ordered pair and whose radius is 9 cm

solong [7]

Answer:

$(x+4)^2+(y-6)^2=81$

Step-by-step explanation:

We want to find equation of a circle with center (-4,6) and radius 9cm.

The equation of a circle with center (h,k) and radius $r$ units is given by;

$(x-h)^2+(y-k)^2=r^2$

We substitute the radius and the center to obtain;

$(x+4)^2+(y-6)^2=9^2$

The required equation is:

$(x+4)^2+(y-6)^2=81$

3 0

2 years ago

Math emended. D d did dnend d d d d d dd

guajiro [1.7K]

Answer:

huh?

Step-by-step explanation:

whats the questionnnnnnn

7 0

2 years ago

Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from

Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that $P = 3000, r = 0.16, n = 1$

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 3000(1 + \frac{0.16}{1})^{t}$

$A(t) = 3000(1.16)^{t}$

(a) Find the amount in the account at the end of 1 year.

This is A(1).

$A(t) = 3000(1.16)^{t}$

$A(1) = 3000(1.16)^{1} = 3480$

(b) Find the amount in the account at the end of 2 years.

This is A(2).

$A(2) = 3000(1.16)^{2} = 4036.8$

4 0

3 years ago

Help please! show work thanks

Andre45 [30]

Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

$b^2 = a^2 + c^2 -2ac \cos B \\ \\
b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\
b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\
b = 2.7708\ m$

b = 2.7708\ m

Find angle A with sine law

$\displaystyle
\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\
\sin A = \frac{a \sin B}{b} \\ \\
A = \sin^{-1} \left[ \frac{a \sin B}{b} \right] \\ \\
A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708} \right] \\ \\
A = 43.0467020$

Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1

6 0

3 years ago

If u help me then i will love you forever

Darina [25.2K]

ok what do u need help with I don't see anything

7 0

2 years ago