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Deffense [45]
2 years ago
7

Which equation best represents the relationship between x and y ?

Mathematics
2 answers:
Butoxors [25]2 years ago
8 0
Y=25x

i hope this is what you’re asking for
Natalija [7]2 years ago
4 0

Answer:

ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

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Dustin works in a department store. He earned $89.00 for working 10 hours last week. At this rate, how much would Dustin earn fo
mr Goodwill [35]

Answer:

$338.20

Step-by-step explanation:

Find out how much Dustin gets for one hour of work, since you are given how much Dustin earns in 10 hours, you divide it by 10 (the number of hours) to find one hour,

89/10=8.9

$8.9 per hour

So 38 hours would be

8.9 x 38= $338.20

5 0
3 years ago
Read 2 more answers
While playing an online game, Reece scored 48
Rudiy27

Answer:

48-(19×2)

=48-38

=10

Reece has 10 points

4 0
3 years ago
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Do banks typically issued credit cards based on a revolving credit agreement
taurus [48]

Answer:

yes

Most credit cards are typically revolving credit agreements.

Step-by-step explanation:

3 0
3 years ago
The graph below shows a proportional relationship between x and y
Snezhnost [94]

Answer:

You get the answer by seeing if the line on the graph passes through the origin and if it does you see how many there is for every 1 thing.

Step-by-step explanation:

3 0
3 years ago
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
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