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masya89 [10]
3 years ago
15

What is the degree?

Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

The answer to the problem is 6

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Determine two pairs of polar coordinates for (3,-3) when 0
Xelga [282]

The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).

<h3>What is a polar coordinate?</h3>

A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

Next, we would determine the distance (r) and angle (θ) as follows:

r = √(3² + (-3)²)

r = √(9 + 9)

r = 3√2.

θ = tan⁻¹(-3/3)

θ = tan⁻¹(-1)

θ = 3π and 7π/4 (second and fourth quadrants).

Converting to degrees, we have:

θ = 135° and 315°.

Read more on polar coordinates here: brainly.com/question/3875211

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Complete Question:

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°

5 0
2 years ago
Evaluate p24-m; use m=3, and p=4
blsea [12.9K]

Answer:

idk

Step-by-step explanation:

3 0
3 years ago
For every 10$ glen earns . his parents require him t0 save 2$ what percent did he spend ?
saveliy_v [14]

Answer:

20%

Step-by-step explanation:

10 each dollar is 10% for 2 dollars =20%

4 0
3 years ago
The cost of performance tickets and beverages for a family of four can be modeled using the equation 4x + 12 = 48, where x repre
Kisachek [45]
4x + 12 = 48
4x = 48 -12
4x = 36
x= 36 / 4
x= 9

Each ticket is $9.
6 0
4 years ago
The coach of the track and field team is putting together groups of runners to run relays. Each group will need to run a race th
andrew11 [14]

Answer:

16 runner

Step-by-step explanation:

It is given that,

Each group will need to run a race that is 1/2 of a mile long. Each runner has to run 1/8 of a mile in the race.

Let there are x no of runners. ATQ,

\dfrac{1}{8}x=\dfrac{1}{2}\\\\x=\dfrac{(1/2)}{(1/8)}\\\\x=16

So, there are 16 runner that are needed for each relay race group.

4 0
3 years ago
Read 2 more answers
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