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3 years ago

Please Help ASAP

Mathematics

1 answer:

Tju [1.3M]3 years ago

3 0

9514 1404 393

Answer:

no solution

Step-by-step explanation:

The discriminant is ...

b^2 -4ac = (-4)^2 -4(2)(16) = 16 -128 = -112

A negative discriminant means there are no real solutions to the equation.

_____

The complex solutions are 1±i√7.

If we assume the equation has a typographical error and is intended to be ...

2x^2 -4x -16 = 0

The solutions are x = -2 and x = 4.

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i will use proportions for this.

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3 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

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3 years ago

If frank has 380 condoms and he uses 180 in two weeks and by the 4th week he has 2 left how many did he use in 2 weeks (btws thi

anastassius [24]

You have said that he used 180 in the first two weeks.

That left him with 200 at the end of the first two weeks.
Then you said that he had 2 left after another 2 weeks.
So during those 2 weeks, he used (200 - 2) = 198 in the 2nd 2 weeks.

What we all expected has not happened at all: Frank is not slowing down !

But, even so, we have to ask ourselves just what Frank is doing with them all.

Nobody can blame you for wondering.

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3 years ago

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A hockey team made four of their 10 attempted goals. which ratio compares the number of goals made to the number of goals attemp

Andrei [34K]

The answer is 4:10. Hope it helps!

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3 years ago

the product of two consecutive integers n and n+1 is 42. what is the positive integer that satisfies the situation?

MrMuchimi

$n(n+1)=42 \\
n^2+n=42 \\
n^2+n-42=0 \\ \\
a=1 \\ b=1 \\ c=-42 \\ b^2-4ac=1^2-4 \times 1 \times (-42)=1+168=169 \\ \\
n=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-1 \pm \sqrt{169}}{2 \times 1}=\frac{-1 \pm 13}{2} \\
n=\frac{-1 -13}{2} \ \lor \ n=\frac{-1+13}{2} \\
n=\frac{-14}{2} \ \lor \ n=\frac{12}{2} \\
n=-7 \ \lor \ n=6$

The positive integer is 6.
The consecutive integers are 6 and 7.

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3 years ago