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rewona [7]
3 years ago
7

What is the solution of the equation? 2^5 sqrt (x+6)^3 +3 =19

Mathematics
2 answers:
kirill [66]3 years ago
5 0

Answer:

x=-5.37

Step-by-step explanation:

The equation is:

2^5\cdot{\sqrt{(x+6)^3}}+3=19

We can simplify by taking over 3 to the left hand side and divide the equation by 2^5 and then squaring both sides to get rid if the square root:

2^5\cdot{\sqrt{(x+6)^3}}=19-3

\sqrt{(x+6)^3}=16/2^5

(x+6)^3=(0.5)^2

(x+6)^3=0.25

We can take the third root on both sides:

(x+6)=0.63

x=0.63-6=-5.37

EleoNora [17]3 years ago
3 0
I got that x=-5.37003947. I am not sure that I put everything under the square root that needed to be there so I hope this helps.
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3 years ago
There is a bag filled with 5 blue and 6 red marbles.
Afina-wow [57]

Answer:

The probability of getting two of the same color is 61/121 or about 50.41%.

Step-by-step explanation:

The bag is filled with five blue marbles and six red marbles.

And we want to find the probability of getting two of the same color.

If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.

In other words, we can find the independent probability of each case and add the probabilities together*.

The probability of getting a red marble first is:

\displaystyle P\left(\text{Red}\right)=\frac{6}{11}

Since the marble is replaced, the probability of getting another red is: \displaystyle P\left(\text{Red, Red}\right)=\frac{6}{11}\cdot \frac{6}{11}=\frac{36}{121}

The probability of getting a blue marble first is:

\displaystyle P\left(\text{Blue}\right)=\frac{5}{11}

And the probability of getting another blue is:

\displaystyle P\left(\text{Blue, Blue}\right)=\frac{5}{11}\cdot \frac{5}{11}=\frac{25}{121}

So, the probability of getting two of the same color is:

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We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.

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3 years ago
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Tpy6a [65]

Answer:

See below

Step-by-step explanation:

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Since 3|(4^k+m), we may conclude, by the axiom of induction, that the property holds for all n\in\mathbb{N}.

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