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Sunny_sXe [5.5K]
3 years ago
13

Is the quotient negative or positive when a negative number is divided by another negative number?

Mathematics
2 answers:
Savatey [412]3 years ago
6 0

Answer:

Positive

Step-by-step explanation:

When a negative number is divided by another negative number, the quotient will be a positive number.

This is because the two negative signs cancel out.

Similarly, the two negative signs also cancel out when multiplying a negative number by another negative number.

So, the quotient will be positive.

Vika [28.1K]3 years ago
3 0

Answer:

IT IS POSITIVE

Step-by-step explanation:

You might be interested in
18m² - 18m³ - 6m <br><br> Factor the common factor
tangare [24]

Answer:

-6m(3m²-3m+6)

or

6m(-3m²+3m-6)

Greatest common factor is 6m or -6m, anyone works.

Step-by-step explanation:

18m² - 18m³ - 6m

The common factor is 6m or -6m, anyone works.

18m² - 18m³ - 6m

-6m(3m²-3m+6)

Hope this helps!

Please mark as brianliest if correct!

7 0
2 years ago
1 5/6 −(x− 7/12 )+2 1/12 =0.9
iren [92.7K]
The answer is x=3.6 or 3 3/5.

First we convert the decimal answer to a fraction; 0.9 is read as "nine tenths," so the corresponding fraction is 9/10:

1 5/6 - (x - 7/12) + 2 1/12 = 9/10

Now we find a common denominator.  The first thing that 6, 12 and 10 will all divide into is 60:

1 50/60 - (x - 35/60) + 2 5/60 = 54/60

Distributing the negative, we have:
1 50/60 - x + 35/60 + 2 5/60 = 54/60

Combining like terms, we have:
-x + 4 30/60 = 54/60

Subtracting 4 30/60 from each side, we have:
-x + 4 30/60 - 4 30/60 = 54/60 - 4 30/60
-x = -3 36/60

Divide both sides by -1:
-x/-1 = (-3 36/60)/-1
x = 3 36/60 = 3 3/5 = 3.6
5 0
3 years ago
Find the missing number
Monica [59]

Answer:

1.3

2.-1

3.1

4.25

5.17

Step-by-step explanation:

maybe i messed up but pretty sure this is it

6 0
3 years ago
Read 2 more answers
7. Let f(x) = 3x and g(x) = (x + 2)^2. Find the value of (f og)(-5)
Keith_Richards [23]

Answer:

plz mark brainliest

thank u

3 0
3 years ago
Consider the cubic function f(x) = x^3 + ax^2 + bx + 4 where (a) and (b) are constants. When f(x) is divided by x-3, the remaind
Debora [2.8K]

Answer:

see explanation

Step-by-step explanation:

Using the Remainder theorem

If f(x) is divided by (x - h) then f(h) = remainder, thus

f(3) = 3³ + a(3)² + b(3) + 4 = 10, that is

27 + 9a + 3b + 4 = 10

9a + 3b + 31 = 10 ( subtract 31 from both sides )

9a + 3b = - 21 → (1)

f(- 1) = (- 1)³ + a(- 1)² + b(- 1) + 4 = 6, that is

- 1 + a - b + 4 = 6

a - b + 3 = 6 ( subtract 3 from both sides )

a - b = 3 → (2)

Rearrange (2) expressing a in terms of b

a = 3 + b → (3)

Substitute a = 3 + b into (1)

9(3 + b) + 3b = - 21 ← distribute and simplify left side

27 + 9b + 3b = - 21

12b + 27 = - 21 ( subtract 27 from both sides )

12b = - 48 ( divide both sides by 12 )

b = - 4

Substitute b = - 4 into (3)

a = 3 - 4 = - 1

Hence a = - 1 and b = - 4

8 0
3 years ago
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