(a) Create a chart of values and write an equation to find the total cost, C in terms of the number of days d.

C = 10d + 20

(b) Use the equation you created in Part (a) to find the cost of renting a bike for 5 days.

C = 10d + 20
C = 10(5) + 20= 50 + 20 = 70

$70 for 5 days

7 0

3 years ago

Solve the equation for x. If necessary round to the nearest tenth. x² = 17 X= +

Ilya [14]

Answer:

x = 4.1 & x = −4.1

Step-by-step explanation:

$x^2 = 17\\$

x = ±√17

x = √17, −√17

x = 4.1 & x = −4.1

7 0

3 years ago

-2(3x + 1) > - 6x + 7

svp [43]

Answer:

I am pretty sure this statement is false so it'd be: x= 0

Step-by-step explanation:

8 0

3 years ago

A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

50 = 200 + C ==> C = -150

so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0

4 years ago