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Gelneren [198K]
3 years ago
9

)

Mathematics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

(1,7), (2,2), (3,5) (4,8)

(2,6), (6,5), (3,2) (5,3)

(4,3), (3,3), (2,3) (1,3)

Step-by-step explanation:

those represent functions b/c the domain of the relation is not written twice

Hope that'll help!

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What is the value of x when -25(x - 4) = -55(x - 10) ?
Free_Kalibri [48]

Simplify both sides of the equation

-25(x-4)=-55(x-10)

(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)

Distribute

-25x+100=-55x+550

Add 55x  to both sides

-25x+100+55x=-55x+550+55x

30x+100-100=550-100

subtract 100 from both sides

30x+100-100=550-100

30x=450

divide both sides by 30

30x/30=450/30

x= 15

The value of x is 15


I hope that's help you my friend !

5 0
3 years ago
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Answer:

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Step-by-step explanation:

-64 * 2/3 is -42.66666...

well, according to the calculator.

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Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
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Answer:

bro no one cares

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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