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2 years ago

13

A student sees a bird on top of a 12m high light pole. The student is standing 20m from the base of the pole. At what angle must

the student incline her camera to take a picture of the bird?

1 answer:

Aleks04 [339]2 years ago

6 0

Answer: 31 degrees

Step-by-step explanation:

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What is a equation in point slope form for a line perpendicular to y=-4x-10 that contains (1,-5)

mixas84 [53]

Y = 1/4x -5

HOPE THIS HELPS

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3 years ago

A scientist makes a graph of temperature versus time. Temperature will be plotted on the ______ axis.

trapecia [35]

Temperature will be plotted on the y-axis

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2 years ago

Read 2 more answers

Virty [35]

Answer:a: y=4.5+0.75x

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3 years ago

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

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3 years ago

winnie and kevin like to create their own triathlon courses to challenge each other. last weekend, winnie created a course that

shepuryov [24]

If you add all of the numerators together
3+57+13= 73
Then you would divide that number by 4
73/4= 18.25
So the course would be 18.25 or 18 1/4 miles long.

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2 years ago