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3 years ago

Can you help me?

Mathematics

1 answer:

4vir4ik [10]3 years ago

5 0

Answer:

Step-by-step explanation:

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Answer 1, 2, and 3.

Rudik [331]

Answer:

a) isosceles right triangle

b) scalene triangle

c) isosceles triangle

d) equilateral triangle

2. 53 degrees

3. Yes. You can use the side-side-side (SSS) postulate because side QR and side SR are shown as congruent, and side QP and SP are also congruent. Since you know that the other two sides are congruent, then that means that the last side must be congruent as well.

Step-by-step explanation:

5 0

2 years ago

If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago

A middle school principal wants to change the lunch menu at the school. The principal surveys the students to determine how the

IceJOKER [234]

I think A or D PLEASE MARK BRAINLIEST

7 0

4 years ago

Read 2 more answers

Express M in terms of B and n: B = 3Mn 2

Molodets [167]

We are given the expression B=3Mn/2 and told to express M in terms of B and n. This means that we should apply mathematical operations on both sides of the equation so we "isolate " M on one side of the equality sign. We begin with the given equation