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olganol [36]
1 year ago
5

Express M in terms of B and n: B = 3Mn 2

Mathematics
1 answer:
Molodets [167]1 year ago
5 0

We are given the expression B=3Mn/2 and told to express M in terms of B and n. This means that we should apply mathematical operations on both sides of the equation so we "isolate " M on one side of the equality sign. We begin with the given equation

B=\frac{3\cdot M\cdot n}{2}

First, we multiply both sides by 2, so we get

2\cdot B=3\cdot M\cdot n

Next, we divide by 3 on both sides, so we get

\frac{2\cdot B}{3}=M\cdot n

Finally, we divide both sides by n, so we get

\frac{2\cdot B}{3\cdot n}=M

In this case, we have succesfully expressed M in terms of B and n

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If I multiplied these binomials (x - 3) + (4x + 2) what would be the final product?
zlopas [31]

Answer: 4x^2 - 10x - 6

Step-by-step explanation:

You can use FOIL to do this. First terms, Outer terms, Inner terms, Last terms.

(x - 3)(4x + 2)

First terms: x * 4x = 4x^2

Outer terms: x * 2 = 2x

Inner terms: -3 * 4x = -12x

Last terms: -3 * 2 = -6

Now add these together:

4x^2 + 2x - 12x - 6 = 4x^2 - 10x - 6

8 0
3 years ago
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A manufacturer considers his production process to be out of control when defects exceed 3%. In a random sample of 100 items, th
pochemuha

Answer:

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

Step-by-step explanation:

A manufacturer considers his production process to be out of control when defects exceed 3%.

At the null hypothesis, we test if the production process is in control, that is, the defective proportion is of 3% or less. So

H_0: p \leq 0.03

At the alternate hypothesis, we test if the production process is out of control, that is, the defective proportion exceeds 3%. So

H_1: p > 0.03

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis

This means that \mu = 0.03, \sigma = \sqrt{0.03*0.97}

In a random sample of 100 items, the defect rate is 4%.

This means that n = 100, X = 0.04

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.04 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{100}}}

z = 0.59

P-value of the test

The p-value of the test is the probability of finding a sample proportion above 0.04, which is 1 subtracted by the p-value of z = 0.59.

Looking at the z-table, z = 0.59 has a p-value of 0.7224

1 - 0.7224 = 0.2776

The p-value of the test is of 0.2776 > 0.01, which means that the we accept the null hypothesis, that is, the manager's claim that this is only a sample fluctuation and production is not really out of control.

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3 years ago
a population of rabbits is growing naturally at 20% each month. if the colony began with 2 rabbits, how many will there be in 5
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The answer is 112695

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2 years ago
What's the area of the quadrilateral ​
shepuryov [24]

Answer: Use the formula (base1+base2)/2 multiplied by height(3 in)

Step-by-step explanation: I can't see what the bottom base is, but lets say it is 12. 5+12=17, and 17/2=8.5. 8.5*3=25.5

Answer:25.5

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Sadie is saving for a new car. Below is the total amount of money in her savings account on the last day of each month. Show all
ICE Princess25 [194]


The mean is 10,724.28.



Explanation:


The mean is all of the values divided by the number of values there are.

So what you have to do is add all of the numbers and divide it by the amount of numbers there are.


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Since there are 7 numbers, divide 75,070/7 and you get your mean, which is 10,724.28 rounded.
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2 years ago
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