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dolphi86 [110]
3 years ago
5

Equation editor does not include the grouping symbols “<“ and “>” that are necessary for writing a vector in component for

m. For this question use braces to write a vector in component form. For example the vector <2,3> should be written as {2.3}.

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

{12,2}

Step-by-step explanation:

From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).

If initial point of a vector is (x_1,y_1) and terminal point is (x_2,y_2), then

\overrightarrow{v}=(x_2-x_1)i+(y_2-y_1)j

Using this formula, we get

\overrightarrow{v}=(7-(-5))i+(2-0)j

\overrightarrow{v}=12i+2j

\overrightarrow{v}=

Using braces, we get

\overrightarrow{v}=\{12,2\}

Therefore, the required vector is {12,2}.

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X²+18x+56=0 by square process
Luba_88 [7]
Solved it and with steps

8 0
3 years ago
Which of the following is a point-slope equation of a line that passes through
Natasha_Volkova [10]

Answer:

y - 4 = -2/3 (x + 1)

Step-by-step explanation:

y2 - y1 / x2 - x1         -2 - 4 / 8 - (-1)      -6/9     = -2/3

y - 4 = -2/3 (x + 1)

7 0
2 years ago
I need this done plz
KIM [24]

Answer:

13. -28 = p

12. 5 = r

11. -12 = t

10. -8 = q

9. -77 = s

8. 9 = w

7. 12 = y

6. 3 = a

5. 9 = n

4. 3 = x

3. 12 = y

2. 5 = c

1. 5 = m

DON'T GET HOOKED

Step-by-step explanation:

13. 1 + p \div 7 = -3 \\ \\ p\div 7 = -4 \\ \\ -28 = p

12. 5[r + 4] = 45 \\ \\ r + 4 = 9 \\ \\ 5 = r

11. t \div 4 - 3 = -6 \\ \\ t \div 4 = -3 \\ \\ -12 = t

10. -4 + 11q = -92 \\ \\ 11q = -88 \\ \\ -8 = q

9. s \div 7 + 8 = -3 \\ \\ s \div 7 = -11 \\ \\ -77 = s

8. w \div 3 + 3 = 6 \\ \\ w \div 3 = 3 \\ \\ 9 = w

7. y \div 3 - 4 = 0 \\ \\ y \div 3 = 4 \\ \\ 12 = y

6. 3[a + 5] = 24 \\ \\ a + 5 = 8 \\ \\ 3 = a

5. 14 = 2n - 4 \\ \\ 18 = 2n \\ \\ 9 = n

4. 3x + 6 = 15 \\ \\ 3x = 9 \\ \\ 3 = x

3. 6y - 11 = 61 \\ \\ 6y = 72 \\ \\ 12 = y

2. 9c - 4 = 41 \\ \\ 9c = 45 \\ \\ 5 = c

1. 2m + 2 = 12 \\ \\ 2m = 10 \\ \\ 5 = m

D O N ' T G E T H O O K E D

___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___

6 1 10 3 9 8 7 13 2 12 11 5 4

I am delighted to assist you anytime!

6 0
3 years ago
What is the discriminant of 3x^2+6x=2
IgorC [24]
ax^2+bx+c=0\\\\the\ discriminant:\Delta=b^2-4ac\\============================\\\\3x^2+6x=2\ \ \ \  \ |subtract\ 2\ from\ both\ sides\\\\3x^2+6x-2=0\\\\a=3;\ b=6;\ c=-2\\\\\Delta=6^2-4\cdot3\cdot(-2)=36+24=\boxed{60}\leftarrow answer
7 0
3 years ago
Edward's cake recipe calls for 15 3/4 cups of flour and
rodikova [14]
Cups of flour=15  3/4=15+ 3/4=(4*15+3)/4=63/4
Cups of sugar=10  1/2=(2*10+1)/2=21/2

We solve this problem by rule of 3:

63/4 cups of flour--------------100 people
x------------------------------------ 25 people

x=(63/4 cups of flout * 25 people)/100 people=1575/400 cups of  flour=
=63/16=(3*16+15)/16=3  15/16  cups of flour.

21/2 cups of sugar-----------------100 people
x-----------------------------------------25 people

x=(21/2 cups fo sugar * 25 people) / 100 people=525/200 cups of sugar= 21/8 =(2*8+ 5)/8=2   5/8 cups of sugar.

Answer:  3  15/16  cups of flour and 2  5/8 cups of sugar.
8 0
3 years ago
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