When 0<x<1 → ⌈x⌉=1 →f(x)=2
when x=0 → ⌈x⌉=0 →f(x)=0
when -1 <x<0 → ⌈x⌉=0 →f(x)=0
when x= -1 → ⌈x⌉= -1 →f(x)= -2
when -2<x<-1 → ⌈x⌉= -1 →f(x)= -2
Answer:
Distance is ![\sqrt{65}](https://tex.z-dn.net/?f=%5Csqrt%7B65%7D)
Step-by-step explanation:
<u><em>Use the distance formula:</em></u>
![\sqrt{(x_{2} - x_{1)^{2} + (y_{2} - y_{1})^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D%20-%20x_%7B1%29%5E%7B2%7D%20%2B%20%28y_%7B2%7D%20-%20y_%7B1%7D%29%5E%7B2%7D%7D)
![\sqrt{(5 - (-2))^{2} + (3 - (-1))^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%285%20-%20%28-2%29%29%5E%7B2%7D%20%2B%20%283%20-%20%28-1%29%29%5E%7B2%7D%20%7D)
![\sqrt{(7)^{2} + (4)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%287%29%5E%7B2%7D%20%2B%20%284%29%5E%7B2%7D%7D)
![\sqrt{49 + 16}](https://tex.z-dn.net/?f=%5Csqrt%7B49%20%2B%2016%7D)
![\sqrt{65}](https://tex.z-dn.net/?f=%5Csqrt%7B65%7D)
Answer:
I could be wrong, but I believe that the answer is D, none. This is because there is only proof of one congruent side and angle.
Step-by-step explanation:
A
D
B
A
C
B
I help you get correct !
It’s b beacuse you have to Dvide by 2