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netineya [11]
3 years ago
15

How do you do 124.2 divided by 23

Mathematics
2 answers:
avanturin [10]3 years ago
8 0
0.54 is the answer to 12.4 divided by 23
n200080 [17]3 years ago
4 0
It's 5.4- I just used the calculator on my phone but I would've just done long division if I didn't have a calculator
You might be interested in
Two angles of a quadrilateral measure 200° and 50°. The other two angles are in a ratio of 2:9. What are the measures of those t
avanturin [10]

Answer:

20° and  90°

Step-by-step explanation:

Let 2x = measure of 1st angle

then 9x =  measure of 2nd angle

The sum of the measures of the angles of a quad is 360

200 + 50 + 2x + 9x = 360

250 + 11x = 360

11x = 110

x = 10

2x = 20°

9x = 90°

7 0
3 years ago
Brian has a gift card with a $250 balance. He buys several video games that cost $33 each. After the purchases, his gift card ba
Leno4ka [110]

Answer: x=6.6969

Step-by-step explanation:

250-(33x)=29

-33x=-221

x=6.6969

5 0
2 years ago
Read 2 more answers
Express 7 min.30sec.as a percentage of 1 hour .​
fgiga [73]

Answer:

well for me

Step-by-step explanation:

7 mins

7×60

=420

plus the 30sec

450 sec

450/3600×100

45000/3600

450/36

12.5

that's how I can help

3 0
3 years ago
Read 2 more answers
10. Mrs. Taylor wants to lay new carpet in the entrance and hallway of her home as shown below. The carpet she selected sells fo
Alona [7]
Don’t u just multiply $2.50 to 2…
6 0
2 years ago
The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at
seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

h \to altitude

b \to base

A \to Area

So:

\frac{dh}{dt} = 1.5cm/min

\frac{dA}{dt} = 1.5^2cm/min

The area of a triangle is:

A = \frac{1}{2}bh

Calculate b when A =88cm^2; h =8cm

A = \frac{1}{2}bh

88=\frac{1}{2} * b * 8

88 =b * 4

Solve for b

b = 88/4

b = 22

We have:

A = \frac{1}{2}bh

Differentiate with respect to time

\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})

Substitute the following values in the above equation

\frac{dh}{dt} = 1.5cm/min        \frac{dA}{dt} = 1.5^2cm/min      b = 22     h = 8

1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)

Multiply both sides by 2

3 = 8 * \frac{db}{dt} + 22 * 1.5

3 = 8 * \frac{db}{dt} + 33

Collect like terms

8 * \frac{db}{dt} = 3 -33

8 * \frac{db}{dt} = -30

Divide both sides by 8

\frac{db}{dt} = -\frac{30}{8}

\frac{db}{dt} = -3.75

4 0
3 years ago
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