Question

A committee of 3 is being formed randomly from the employees at a school: 5 administrators, 34 teachers, and 4 staff. What is the probability that all 3 3 members are administrators? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Answer 1

Answer:0.000810

Step-by-step explanation:

Given

A committee of 3 members is formed using

5 Admin, 34 teachers, and 4 staff

Favorable outcomes are selecting 3 members as Administrators

total members =5+34+4=43

Probability is given by

$\Rightarrow P=\dfrac{\text{Favorable}}{\text{Total}}$

$\Rightarrow P=\dfrac{^5C_3}{^{43}C_3}=\dfrac{10}{43\times 41\times 7}\\\\\Rightarrow P=\dfrac{10}{12,341}=0.000810$