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ahrayia [7]
3 years ago
8

Solve the system by graphing y=-2x + 2 y=-2x - 2

Mathematics
1 answer:
german3 years ago
6 0

Answer:

<u>hope it helps...</u>

<u>have a great day!!</u>

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Lucia walks 2/4 miles on Monday. on Tuesday, she walks 1 1/2 times farther. How far did Lucia walk on Tuesday?
alexdok [17]

Answer:

13/6 I think

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4 0
3 years ago
Whats 7/15 as a decimal
mezya [45]

Answer:

0.46666667

Step-by-step explanation:

https://thefractioncalculator.com/FractionAsaDecimal/What-is-7/15-as-a-decimal.html

3 0
3 years ago
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( ONLY ANSWER THIS IF YOU KNOW WHAT THE ANSWER IS) I will give Brainliest!
vodka [1.7K]

Answer:

?

Step-by-step explanation:

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4 years ago
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Vihaan finds that the roots of a quadratic equation that contains a difference of squares pattern is x = +-16. What is true abou
tigry1 [53]

The answer to the question, <u>What is true about the graph of the parabola described by the quadratic equation</u> is that the parabola crosses the x-axis at x = ±16.

Since the quadratic equation has roots x = ±16, it implies that its factors are x - 16 and x + 16.

So, the quadratic equation is y = (x - 16)(x + 16) = x² - 16²

Also, we know that the roots of a quadratic equation are the points where the value of the quadratic equation equals zero. At this value, the quadratic equations crosses the x-axis at the roots of the quadratic equation.

Since the roots of our quadratic equation are x = ±16, it implies that the parabola crosses the x-axis at x = ±16.

So, the answer to the question, <u>What is true about the graph of the parabola described by the quadratic equation</u> is that the parabola crosses the x-axis at x = ±16.

Learn more about quadratic equations here:

brainly.com/question/18162688

5 0
3 years ago
Find an equation for the perpendicular bisector of the line segment whose end points are (-9,-8) and (3,-2)
Sunny_sXe [5.5K]

Answer:

y=-2x-11

Step-by-step explanation:

Slope of the line segment = [(-8)-(-2)]/[(-9)-3]=-6/-12=1/2

Slope of the perpendicular bisector x slope of line segment = -1

Slope of perpendicular bisector = -2

Mid-point of line segment = ((-9+3)/2, (-8+(-2))/2) = (-3, -5)

The perpendicular bisector passes through the mid-point.

By point-slope form,

\frac{y-(-5)}{x-(-3)} = -2\\y+5=-2x-6\\y=-2x-11

4 0
3 years ago
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