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nalin [4]
2 years ago
6

Someone PLEASE help me !!

Mathematics
2 answers:
borishaifa [10]2 years ago
7 0

Answer:

no lo entiendo lo que escribiste

alukav5142 [94]2 years ago
6 0

Answer:

1.5(x+y)/z

2. 7(x+y)-5/3z

3.1/2(x+y)-5

4. 3x-4y/7z

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Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in
kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let y\in (x-\epsilon,x+\epsilon). then we have that x-\epsilon. Hence, it makes sense to define the positive number delta as \delta=\min\{x+\epsilon-y,y-(x-\epsilon)\} (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon), and if we prove this, we are done. To prove it, let z\in (y-\delta,y+\delta), then y-\delta. First, \delta \leq y-(x-\epsilon) then -\delta \geq -y+x-\epsilon hence z>y-\delta \geq x-\epsilon

On the other hand, \delta \leq x+\epsilon-y then z hence z. Combining the inequalities, we have that  x-\epsilon, therefore (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon) as required.  

3 0
3 years ago
Please help!!!!
DochEvi [55]

Answer:

256h28k8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0
3 years ago
The function h(x) is given below.
Nutka1998 [239]

Answer:

Step-by-step explanation:

I wish I knew :(

8 0
3 years ago
Arrange these numbers from least to greatest
iogann1982 [59]
A. -3/7 = -0.4286
b. -5/6 = -0.8333
c. -3/5 = -0.6000
d. -7/9 = -0.7777
bdca is least to greatest

Correct answer is D.
4 0
3 years ago
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