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Makovka662 [10]
3 years ago
14

Find the value of X. Please help ASAP!! I have no idea how to do this and I have to have it done soon!!

Mathematics
1 answer:
Temka [501]3 years ago
5 0

Answer:

x=\frac{3}{4}=0.75

Step-by-step explanation:

From the shape of the quadrilateral, we can assume that it is a parallelogram. In a parallelogram, opposite sides are congruent and thus have the same length.

In this case, we are given that two opposite sides have lengths of 4x+5 and 8. Therefore, since the quantities must be equal, we can write the following equation to solve for x: 4x+5=8. Solving for x, we get:

4x+5=8

4x=3 (Use the Subtraction Property of Equality to subtract 5 from both sides of the equation, which isolates x)

x=\frac{3}{4} =0.75 (Use the Division Property of Equality to divide both sides of the equation by 4 to get rid of x's coefficient)

Hope this helps!

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6 0
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olga nikolaevna [1]

\left\{\begin{array}{ccc}x+3y-z=2\\4x+2y+5z=1\\3x+z=12&\to z=12-3x\end{array}\right\\\\\text{substitute the value of z to the first and second equation}\\\\\left\{\begin{array}{ccc}x+3y-(12-3x)=2\\4x+2y+5(12-3x)=1\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y-12+3x=2&|+12\\4x+2y+60-15x=1&|-60\end{array}\right\\\\\left\{\begin{array}{ccc}4x+3y=14&|\cdot2\\-11x+2y=-59&|\cdot(-3)\end{array}\right

\underline{+\left\{\begin{array}{ccc}8x+6y=28\\33x-6y=177\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ \ \ 41x=205\ \ \ \ |:41\\.\ \ \ \ \ \ \ x=5\\\\\text{substitute the value of x to the first equation}\\\\4(5)+3y=14\\20+3y=14\ \ \ \ |-20\\3y=-6\ \ \ \ \ |:3\\y=-2\\\\\text{substitute the value of x to the equation:}\ z=12-3x\\\\z=12-3(5)=12-15=-3\\\\x=5,\ y=-2,\ z=-3\to(5,\ -2,\ -3)

6 0
3 years ago
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