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3 years ago

Please help I need help

Mathematics

1 answer:

aliina [53]3 years ago

8 0

It think the answer could quite possibly be 4

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HELP ASAP! Will name brainliest!

eimsori [14]

Answer:

mean:8,median:8,mode:8

Step-by-step explanation:

sori cant do the second one

8 0

2 years ago

Two angles of a quadrilateral are 40 degree and 60 degree and the ratio of remaining two angles is 7:6. The degree measure of re

Semenov [28]

Answer:

140,120

Step-by-step explanation:

sum of angles in a quadrilateral =360

sum of the 1st two angles=60+40=100

360-100=260

the ratio of the remaining angles 7:6

therefore:

$\frac{7}{13} \times 260$

=140

for the second angle

260-140=120

5 0

2 years ago

Simplify the following expression 4w x 3w x 2y x 2y

Anestetic [448]

Answer:

48w^2y^2

I used a simplify calculator I hope this is correct.

4 0

3 years ago

Read 2 more answers

The surface area for a rectangular prism with a square base is SA=2s2+4sh. What is the surface area if s=3 and h=5?

Zigmanuir [339]

Answer:

The surface area is 78 unit square.

Step-by-step explanation:

Given : The surface area for a rectangular prism with a square base is $SA=2s^2+4sh$ .

To find : What is the surface area if s=3 and h=5?

Solution :

The surface area for a rectangular prism with a square base is $SA=2s^2+4sh$

Substitute, s=3 and h=5

$SA=2(3)^2+4(3)(5)$

$SA=2\times 9+4\times 15$

$SA=18+60$

$SA=78$

Therefore, The surface area is 78 unit square.

7 0

2 years ago

A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di

denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is $0.432\, \frac{m}{s^{2}}$

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , $V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}$

Now centripetal acceleration is given by

$a_c=\frac{V^{2}}{R}$

where $V= 4.0\frac{m}{s}$

$Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m$

$\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}$

Thus her centripetal acceleration during the turn at each end of the track is $0.432\, \frac{m}{s^{2}}$

4 0

3 years ago

Read 2 more answers