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3 years ago

Given the coordinates of a rectangle A(2,5) B(6,5) C(6,-5) and D(2,-5), write the equations of the lines of reflection

Mathematics

1 answer:

Natalija [7]3 years ago

5 0

Answer: D

Step-by-step explanation: because I got the same question and got it right

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The equation of a parabola changes from y = x2 − 2 to y = x2 + 5. What transformation best describes the change in the equation?

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I'm not totally sure the exact answer, or if this even helps, but the Y intercept is changing from -2 to 5

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4 years ago

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Reduce fraction: a^3+a^2b/5a times 25/3b+3a

Margaret [11]

ANSWER

$\frac{5a}{3}$

EXPLANATION

The given fractions are:

$\frac{{a}^{3} + {a}^{2} b}{5a} \times \frac{25}{3b + 3a}$

We factor to obtain:

$\frac{{a}^{2}(a + b)}{5a} \times \frac{25}{3(a + b)}$

We cancel the common factors to get:

$\frac{{a}(1)}{1} \times \frac{5}{3(1)}$

We multiply the numerators and also multiply the denominators to get:

$\frac{5a}{3}$

Therefore the two fractions simplifies to $\frac{5a}{3}$

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4 years ago

Find the volume of a right circular cone that has a height of 3.2 m and a base with a

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3 years ago

How do I find the surface area of a cone

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3 years ago

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

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3 years ago