What is 9^2+a= square root of 113 what is the value of a

Rush! please please help

kodGreya [7K]

Answer:

it's the one on the bottom right of the screen

5 0

3 years ago

Rp+s=t in terms of r, s,and t

expeople1 [14]

Answer:

p=(t-s)/r

Step-by-step explanation:

This is an equation so all we have to do is solve backwards step by step:

rp+s=t

rp+s-s=t-s

rp/r=(t-s)/r

p=(t-s)/r

8 0

3 years ago

In circle O, RT and SU are diameters. If m = m, what is m? 47° 52° 64° 87°

vlada-n [284]

From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.

13x = 15x - 8
15x - 13x = 8
2x = 8
x = 8/2 = 4

Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.

RT is a diameter, which means that mRT = 180

mRV + mVU + 52 = 180

mRV + mVU = 180 - 52 = 128

Now, given that mRV = mVU,

Thus, 2mVU = 128

Therefore, mVU = 128 / 2 = 64°

8 0

3 years ago

Read 2 more answers

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

Mrs. Habib has 46.25 feet of border for a bulletin board for her classroom. the board is 37.5 feet tall and 8.3 feet wide. how m

Luba_88 [7]

Answer:

Mrs. Habib will have 22.25 feet of border left after she puts border around the board.

Step-by-step explanation:

You must find the perimeter of the board and subtract it from the amount of border she has to find how much she will have left after she uses it. The formula for perimeter is $P=2(l+w)$ , where $l=$ the length of the board, and $w=$ the width of the board. You will add those together and multiply them by 2 because there are 4 sides to a rectangle. That means this equation will look like:

$P=2(8.25+3.75)$

Now you can just solve for the perimeter.

$P=2(12)$

$P=24$

The perimeter is 24 feet. That means it will take 24 feet of border to cover her board. In order to find out how much she'll have left over, just subtract 24 from the total amount of border she has.

$46.25-24=22.25$

Therefore Mrs. Habib will have 22.25 feet of border left over after she covers the bulletin board.

7 0

3 years ago