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melamori03 [73]
3 years ago
9

Choose the answer that best completes the sentence below.

Mathematics
1 answer:
krok68 [10]3 years ago
8 0
The answer is "while".

"While foot binding was promoted as a way to achieve ideal beauty, in reality, it horribly disfigured a woman's feet."
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can someone please answer the first four for me? Also can someone please explain it to me, because I don't fully understand​
pentagon [3]

1                           2

a^{2} +b^{2} =c^{2} \\9^{2} + 13^{2} =c^{2}\\81+169=c^{2} \\250=c^{2} \\125=c        a^{2} +b^{2} =c^{2} \\16^{2} +18^{2} =c^{2} \\256+324=c^{2} \\580=c^{2} \\290=c

3                          4

a^{2} +b^{2} =c^{2} \\19^{2} +14^{2} =c^{2} \\361+196=c^{2} \\557=c^{2} \\278.5=c      a^{2}+ b^{2}=c^{2} \\10^{2} +11^{2}=c^{2} \\100+121=c^{2} \\221=c^{2} \\110.5=c

6 0
3 years ago
Antonio ran 129 laps at the park. Alan ran 20% more than that. how many laps did Alan run
Colt1911 [192]

Answer:

154.8

Step-by-step explanation:

20% is equal to 20/100= 0.20. So, 0.20 multiplied by 129 will give you 20% of 129 which is 25.8. If Alan ran 20% more then you add 25.8 to 129 which gives you an answer of 154.8.

Equation: 20/100= 0.2

                0.2* 129= 25.8

                25.8+129= 154.8

Alan ran 154.8 laps.

3 0
3 years ago
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
Help with this number 3)is 2×=-8
IRISSAK [1]
2x= -8
2x/2=-8/2
X= -4
6 0
3 years ago
PLEASE HELPPPPPP!!!!!!Solve this system of linear equations separate the x-and y-values with a comma
GenaCL600 [577]

Answer:

x=-6,\\y=6

Step-by-step explanation:

Rewrite the system of equations as:

\begin{cases}-13x+2y=90\\-6x+2y=48\end{cases}

Subtract the second equation from the first to isolate x:

-13x+2y-(-6x+2y)=42,\\-7x=42, \\\fbox{$x=-6$}

Plug in x=-6 into any of the equations above and solve for y:

-6(-6)+2y=48,\\2y=12,\\\fbox{$y=6$}

Verify that the solution pair (-6, 6) works \checkmark

Therefore, the solution to this system of equations is:

x=-6,\\y=6

8 0
3 years ago
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