Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output
A hypothetical company that needs an information system is Memphis drilling and construction company.
<h3>What is the size of a project?</h3>
This is known to be the the number of firms taking part in the project and thus in the case above, it is small project.
In terms of Staff/experts availability, there are experts from the mining industry with years of experience, soil survey analyst as well as other minor staff.
In terms of System level of criticality, it is big because the extent to drilling will make use of the information system and other major decisions made.
Learn more about information system from
brainly.com/question/14688347
#SPJ1
Answer:
import java.util.Scanner;
public class TestClock {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter two integer numbers");
int num1 = in.nextInt();
int num2 = in.nextInt();
int newSum=num1+10;
System.out.println("The first number is "+num1);
do{
System.out.println(newSum);
newSum +=10;
}while (newSum <=num2);
}
}
Explanation:
Using Java Programming language
- Prompt user for the two inputs and save them as num1 and num2(Using the scanner class)
- Create a new Variable newSum = num1+10
- Create a do...while loop to continually print the value of newSum, and increment it by 10 while it is less or equal to num2
The answer is (d.) display and pilot light
An automatic drip coffee maker displays two output from the digital controller; the time and the light or output signal. According to the US Patents publication, an automatic drip coffee maker includes a timer circuit. It's to provide pre-selected time for the activation and deactivation of the coffee maker.
1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.
