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3 years ago

Not sure how to do this

Mathematics

1 answer:

Stolb23 [73]3 years ago

3 0

Answer:
Scale factor of 2

Explanation:
I compared the lengths of AC to DF. AC is one unit long, whereas DF is two units long, so DF is dilated by a scale factor of 2.

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Which of the following statements must be true based on the diagram below?(Diagram is not to scale.)FDEO EF is a segment bisecto

8_murik_8 [283]

From the diagram given;

ABCD is a quadrilateral;

Line |EF| bisects the line |AD| and line |CD|,

Thus, from the given options;

LINE |EF| is a segment bisector is the only correct option.

6 0

1 year ago

6a+(8b+2a)=6a+(2a+8b)=0 <br><br>please help me solve this

solniwko [45]

<span>Simplifying (6a + -8b)(6a + 8b) = 0 Multiply (6a + -8b) * (6a + 8b) (6a * (6a + 8b) + -8b * (6a + 8b)) = 0 ((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0 Reorder the terms: ((48ab + 36a2) + -8b * (6a + 8b)) = 0 ((48ab + 36a2) + -8b * (6a + 8b)) = 0 (48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0 (48ab + 36a2 + (-48ab + -64b2)) = 0 Reorder the terms: (48ab + -48ab + 36a2 + -64b2) = 0 Combine like terms: 48ab + -48ab = 0 (0 + 36a2 + -64b2) = 0 (36a2 + -64b2) = 0 Solving 36a2 + -64b2 = 0 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '64b2' to each side of the equation. 36a2 + -64b2 + 64b2 = 0 + 64b2 Combine like terms: -64b2 + 64b2 = 0 36a2 + 0 = 0 + 64b2 36a2 = 0 + 64b2 Remove the zero: 36a2 = 64b2 Divide each side by '36'. a2 = 1.777777778b2 Simplifying a2 = 1.777777778b2 Take the square root of each side: a = {-1.333333333b, 1.333333333b}</span>

4 0

3 years ago

How do u write 5(2x - 1) in a distributive property

Nookie1986 [14]

Answer:

5(2x-1) = 5(2x) - 5(1)

Step-by-step explanation:

The distributive property states that multiplying a sum or difference of two terms by a number is equal to multiplying the same number with each term of the sum or difference separately and then adding the products.

It can be written as:

a(b+c) = ab + ac

a(b-c) = ab - ac

So, for the given question,

=>5(2x-1) = 5(2x) - 5(1)

5 0

3 years ago

Look at pic 10 pts will mark brainilest

seropon [69]

Answer:

c may be the correct one l am 55% sure

6 0

2 years ago

Read 2 more answers

A study of long-distance phone calls made from General Electric's corporate headquarters in Fairfield, Connecticut, revealed the

Jet001 [13]

Answer:

a) 0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

b) 0.0668 = 6.68% of the calls last more than 4.2 minutes

c) 0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

d) 0.9330 = 93.30% of the calls last between 3 and 5 minutes

e) They last at least 4.3 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 3.6, \sigma = 0.4$

(a) What fraction of the calls last between 3.6 and 4.2 minutes?

This is the pvalue of Z when X = 4.2 subtracted by the pvalue of Z when X = 3.6.

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

X = 3.6

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.6 - 3.6}{0.4}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

0.9332 - 0.5 = 0.4332

0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

(b) What fraction of the calls last more than 4.2 minutes?

This is 1 subtracted by the pvalue of Z when X = 4.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% of the calls last more than 4.2 minutes

(c) What fraction of the calls last between 4.2 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 4.2. So

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

0.9998 - 0.9332 = 0.0666

0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

(d) What fraction of the calls last between 3 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 3.

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 3

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3 - 3.6}{0.4}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.9998 - 0.0668 = 0.9330

0.9330 = 93.30% of the calls last between 3 and 5 minutes

(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time?

At least X minutes

X is the 100-4 = 96th percentile, which is found when Z has a pvalue of 0.96. So X when Z = 1.75.

$Z = \frac{X - \mu}{\sigma}$

$1.75 = \frac{X - 3.6}{0.4}$

$X - 3.6 = 0.4*1.75$

$X = 4.3$

They last at least 4.3 minutes

7 0

3 years ago