All categories

3 years ago

Use the pythagorean theorem 1) a=7 b=12

Mathematics

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

√193

Step-by-step explanation:

7^2 = 49

12^2 = 144

144 + 49= 193

√193 because you are trying to find c not c^2

You might be interested in

Claire has invested $10,000 in an 18-month CD that pays 6.25%. How much interest will Claire receive at maturity?

Vikki [24]

Answer:

the interest received is $957.03

Step-by-step explanation:

Given that

The invested amount is $10,000

There is 18 months

And, the interest rate is 6.25%

= (($10,000 × (1 + 6.25% ) × 0.0625 × 6 months ÷ 12 months)) + ($10,000 × 6.25%)

= $332.03 + $625

= $957.03

Hence, the interest received is $957.03

4 0

2 years ago

(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)

GrogVix [38]

I believe it's

- 1 - $\frac{4}{n - 2}$

Hope I helped! ( Smiles )

7 0

3 years ago

Read 2 more answers

Given right triangle MUD such that mD = 23.1 and d = 38, which of the following statements are true? Round to the nearest hundre

Zigmanuir [339]

∠M=90°-23.1°=66.9° - it's a right answer.

u=d/sin∠D=97.25
m=cos∠D*u=89.52

4 0

3 years ago

Read 2 more answers

Express 3 to the powermof -2 as rational number

faltersainse [42]

Answer:

(2/3)³

2³/3³

2³ × 3^(-3)

Step-by-step explanation:

3 0

3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

3 years ago

Read 2 more answers