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Liula [17]
3 years ago
6

Hopkins has a 1 meter wire using to make clocks. Each fourth meter is marked off and divided into 5 smaller equal lengths.

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Complete question :

Mr. Hopkins has a 1 meter wire he is using to make clocks. Each fourth meter is marked off with 5 smaller equal lengths. If Mr. Hopkins bends the wire at ¾ meter, what fraction of the marks is that?

Answer:

15 th ; 15/20

Step-by-step explanation:

Length of wire = 1 m

Number of fourth length possible = 1 ÷ 1/4 = 1 * 4/1 = 4

Each fourth length divided into 5 equal sizes :

Hence. Total number of equal spaced division :

5 * 4 = 20

If wire is bent at 3/4 meter :

Fraction of the mark

3/ 4 of 20

3/4 * 20

(3 * 20) / 4

60 / 4

= 15th

= 15/ 20

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There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
3 years ago
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Answer:

x = 3.3

Step-by-step explanation:

A equation is given to us and we need to solve out for x. The given equation is ,

Take log on both sides with base as " 10" . We have ,

Simplify using the property of log ,  , we have ,

Simplify ,

Again simplify using the property of log ,

We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,

Simplify the RHS ,

Add 2 both sides ,

Hence the Value of x is 3.30 .

3 0
2 years ago
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3 years ago
X = [?]<br> 5x - 5<br> 2x + 10
Ket [755]

Answer:

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Step-by-step explanation:

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3 years ago
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serious [3.7K]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
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