The interval notation for numbers greater than 2 but less than or equal to 20 is (2,20]
Answer:
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Answer:
y-coordinate is 5 or -1.
Step-by-step explanation:
Point A is at (x, 2) and B is at (x+6, 2). Since AB must lie on the line y=2 and be 6 units long. Point C is on the line x = -3 . So let C be at (-3, y).
Since ΔABC is a right angle, then point C must have the same x-coordinate as point A. Therefore, A(-3, 2) and B(2, 2).
The area of ΔABC is 6. So,
9 = 1/2 (b)(h)
where b is the base and h is the height.
so b = 6 and h = AC
Solving this for C gives
9 = 1/2 (6)(AC)
18/6 = AC
3 = AC
9 = 1/2 (6)(AC)
18/6 = AC
3 = AC
Point C must lie 3 units above point A or 3 units below the point A. If it lies 3 units above, then it has a y-coordinate of 2 + 3 = 5.
If it lies 3 units below, it has a y-coordinate 2 - 3 = -1.
Therefore, y-coordinate is 5 or -1.
Step-by-step explanation:
Answer:
this is the method of elimination and how to do it
Hope this helps :))
<span>In finding the solution for x, the idea is to isolate the variable on one side of the equation
5 - 3x = 2x + 9 |3x is added to the equation first
5 = 5x + 9 | 9 is subtracted from EQ second
-4 = 5x </span>