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erma4kov [3.2K]
2 years ago
8

Chooseeeeeeeeeeeeeeeee oneeeeeeee plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz and explain ​

Mathematics
1 answer:
vova2212 [387]2 years ago
8 0

Answer:

Step-by-step explanation:

Jose is right because the two angles are coresponding angles that are congruent

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Which of the following rules describes the pattern in the table?
sattari [20]

Answer:

b = e + 4

b = e + 4 i think that is the pattern in the table

6 0
3 years ago
Using long division to find the quotient, what changes do you first
lora16 [44]

Answer:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

Step-by-step explanation:

Given

Dividend = 125x^3 - 8

Divisor = 5x - 2

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

\frac{125x^3}{5x} =25x^2

Write 25x^2 at the top

Multiply 5x - 2 by 25x^2

= 125x^3 - 50x^2

Subtract from 125x^3 - 8

i.e.

125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8

Step 2:

Divide 50x^2 by 5x

\frac{50x^2}{5x} = 10x

Write 10x at the top

Multiply 5x - 2 by 10x

= 50x^2 - 20x

Subtract from 50x^2 - 8

i.e.

50x^2 - 8 - (50x^2 - 20x) = 20x - 8

Step 3:

Divide 20x by 5x

\frac{20x}{5x} = 4

Write 4 at the top

Multiply 5x - 2 by 4

= 20x - 8

Subtract from 20x - 8

i.e.

20x - 8 - (20x - 8) = 0

Hence:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

8 0
3 years ago
Edge proof would be amazing and I will give brainliest for it!
inna [77]

Answer: The answer is B.

Step-by-step explanation: The scale on the y-axis could be changed to 100–120.

7 0
11 months ago
Rosemary walks each week for exercise. Let d represent the distance walked and h represent the number of hours spent walking.
nadya68 [22]
Ok last week she walked 18/6 which equals 3 and 3 is less than 2.5. 2.5h is really just that times how many hours.D is the amount of miles.So,the awnser is going to  be b or d.But we dont know what d is in d=2,5h so we have to asume that b is the awnser
8 0
3 years ago
Read 2 more answers
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
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