3 years ago

What is the formula for the surface area of a triangular pyramid

Mathematics

1 answer:

denis23 [38]3 years ago

4 0

$4(b \times h) \div2$

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the image shows reduction

Step-by-step explanation:

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Given: ΔPSQ, PS = SQ Perimeter of ΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ

Lana71 [14]

Answer:

120 units²

Step-by-step explanation:

Perimeter = PS + SQ + PQ

50 = SQ + SQ + (SQ -1)

51 = 3SQ

17 = SQ

17 -1 = 16 = PQ

The midpoint of the base is one leg of the right triangle whose other leg is the height of this isosceles triangle. That height is ...

h = √(17² -(16/2)²) = √225 = 15

Then the area is ...

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The traveling time would be 470,588.235294km/hr

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3 years ago

Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)

vlabodo [156]

We know that $\log_a(bc)=\log_a(b)+\log_a(c)$ .

Using this rule,

$\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)$ .

We also know that $\log_c(a^b)=b\log_c(a)$ .

Using this rule,

$\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)$

Now we know that $\log_c(A)=2,\log_c(B)=5$ so,

$5\cdot2+3\cdot5=10+15=\boxed{25}$ .

Hope this helps :)

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2 years ago