Ask question

Ask question

All categories

3 years ago

7

Отремонтировали три отрезка шоссе дли- ной 5,5 км, 10,9км и 11,1 км. Сколько денег потратило государство на ремонт дороги, если

ремонт 1 км стоит в среднем 91 000 €?

1 answer:

fgiga [73]3 years ago

4 0

общий:2502500

отвечать:

5.5km = 500500

10.9km=991900

11.1km=1010100

Пошаговое объяснение:

5.5x91000=500500

10.9x91000=991900

11.1x91000=1010100

You might be interested in

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

Classify each polynomial as a monomial, binomial, or trinomial. Combine like terms first.

brilliants [131]

Classify each polynomial as a monomial, binomial, or trinomial. Combine like terms first.

We can classify the polynomial according to the number of terms

If we have one term then it is monomial

If we have two terms then it is binomial

If we have three terms then it is trinomial

(1) $x^3 + 3x^3 + 2x$

$4x^3 + 2x$

We have two terms so it is Binomial

(2) $2x^3 + 5x + 3x^4 - x$

$2x^3 + 4x + 3x^4$

We have three terms so it is Trinomial

(3) $4x - 5x + x - 2$

$4x - 5x + x - 2$

-2

We have one term so it is monomial

(4) $6x^2 + 5 - 2x^2 - 9$

$4x^2 - 4$

We have two terms so it is Binomial

7 0

3 years ago

Read 2 more answers

Help me on number 2 please . The number on the rectangle says<br> 18x^2 +12x+2

swat32

2* (9x2squared -6 * -1 )

5 0

4 years ago

In an experiment, the temperature of a sample is measured as 16 degrees Celsius. If the percent error is 0.75%, how can you repo

dsp73

Answer: T=16 ± 0.12 ° CA Aw

Step-by-step explanation:

3 0

3 years ago

Your boss hands you the monthly data that show the number of orders coming in to and out of the warehouse. The data are in the t

Flauer [41]

So the number of orders in is y=x+2, and going out is y=2x-1. The solution, which is x=3, represents when the number of order in is the same as the number of order out.

4 0

3 years ago

Read 2 more answers