Question

Please help!!! 15 point

Answer 1

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Answer:

  sin(θ)tan(θ)

Step-by-step explanation:

  $\dfrac{\cos\theta}{\csc^2\theta-1}=\dfrac{\cos\theta}{\cot^2\theta}=\cos\theta\cdot\tan^2\theta=\cos\theta\cdot\dfrac{\sin\theta}{\cos\theta}\cdot\tan\theta\\\\=\boxed{\sin\theta\cdot\tan\theta}$