Which point on the scatter plot is an outlier? A graph shows scale on x axis from 0 to 14 at increments of 2 and a scale on y ax
is from 0 to 70 at increments of 10. Dots are made at ordered pairs 0, 0 and 1.8, 5 and 2.3, 9 and 2.8, 11 and 3.5, 15 and 4.1, 22 and 4.2, 26 and 5.5, 18 and 5.8, 29 and 6, 30 and 6.1, 15 and 6.5, 32 and 7.2, 35 and 7.3, 38 and 8.5, 42. The point 12, 10 is labeled as P, the point 6, 40 is labeled as Q, the point 3, 20 is labeled as R, and the point 0, 0 is labeled as S. Point P Point Q Point R Point S
2 answers:
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Answer:
Tan(b°) = 3/4 = three fourths (C)
Step-by-step explanation:
Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°
We would apply SOHCAHTOA from trigonometry to determine the value for each sides.
For ∆JKL
Sin(b°) = opposite/hypotenuse
Sin(b°) = 3/5
Cos(b°) = adjacent/hypotenuse
Cos(b°) = 4/5
Tan(b°) = 3/4
From the above we know the value of each sides of ∆JKL
Find attached the diagram of the above triangle (1)
∆JKL is dilated by a scale factor = 2
Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:
Opposite = 2(3) = 6
Adjacent = 2(4) = 8
Hypotenuse = 2(5) = 10
To find tan(b°) of the new triangle, we would apply tangent ratio
Tan(b°) = opposite/adjacent
Tan(b°) = 6/8
Tan(b°) = 3/4
Find attached the diagram for the new triangle (2)
Diagram 3 shows the drawing of both triangles together.
From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.
Therefore, tan(b°) = three fourths (C)
