Let the time Shelia spend on the road be t. Thus, the time Allison spends on the road will be t-2 (assuming t is at least 2 hours).
Since distance is speed*time, we want the time when the distance Allison and Shelia to be the same:



Therefore, Allison will catch up the Shelia after Shelia is on the road for 8 hours (6 hours driving time for Allison).
Answer:
A
Step-by-step explanation:
U can already eliminate C and D since the z needs to be with 2. A and B almost look the same but in the radicals the second number goes on top resulting in 5/6 which leads to A.
(4*0.1+10x)/14=0.35
0.4+10x=4.9
10x=4.5
x=0.45
The B ink is 45% blue.