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Pie
3 years ago
11

Find the slope of the line tangent to the function y=6-3x at the point (5,0)

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer:

-3

Step-by-step explanation:

To get the slope of the line tangent to the function y = 6 - 3x

First, we need to differentiate;

dy/dx = 0 -3x^{1-1}

dy/dx = 0 - 3x^0

dy/dx = 0 - 3

dy/dx = -3

Hence the slope of the line tangent to the function at the point is -3

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The median is 15
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Which expression is equivalent to<br> logbase12 ((1/2)/8w)?
Lunna [17]

\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of rationals} \\\\ log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_{12}\left( \cfrac{~~\frac{1}{2}~~}{8w} \right)\implies \begin{array}{llll} \log_{12}\left( \frac{1}{2} \right)&-&\log_{12}(8w)\\\\ \log_{12}(1)-\log_{12}(2)&-&[\log_{12}(8)+\log_{12}(w)] \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \log_{12}(1)-\log_{12}(2)-\log_{12}(8)-\log_{12}(w)~\hfill

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3 years ago
Which of the following expressions are equivalent to - -13/12
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2 years ago
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