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Lubov Fominskaja [6]
2 years ago
7

Dont answer this question if you dont know the answer

Mathematics
1 answer:
faltersainse [42]2 years ago
6 0

Answer:

B

Step-by-step explanation:

 

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PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK
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Answer:

\huge\boxed{9}

Step-by-step explanation:

\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}

Rule of exponents a^0 = 1 , 1/a^m = a^{-m}

=> \sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}

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Combining same bases

=> \sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}

When bases are same , powers are to be added

=> \sf 2 ^{-16-12+28} * 3^{10-8}

=> \sf 2^{-28+28} * 3^2

=> \sf 2^0 * 3^2

=> \sf 3^2

=> 9

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