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2 years ago

Circle theorem - find p

Mathematics

1 answer:

kow [346]2 years ago

4 0

Answer:

Step-by-step explanation:

the angle in a semicircle = 90° , that is the 3rd angle in the triangle.

the sum of the 3 angles in a triangle = 180° , then

p + 90° + 42° = 180°

p + 132° = 180° ( subtract 142° from both sides )

p = 48°

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

kati45 [8]

Answer:

42.39 cubic feet

Step-by-step explanation:

7 0

3 years ago

Evan bought 7 books on

cluponka [151]

He saved $1.75 per book.
($57.75/7) - ($45.50/7)
$8.25 - $6.50 = $1.75

4 0

2 years ago

You are buying decorations for a birthday party. Six rolls of crepe paper and 20 balloons cost $11.90. After you start decoratin

olga2289 [7]

Answer: $1.15

Step-by-step explanation:

The question is How much did each roll of crepe paper cost?

Let the cost of crepe paper be x

Let the cost of balloons be y.

Six rolls of crepe paper and 20 balloons cost $11.90. This will be:

6x + 20y = 11.90 ......... i

2 more rolls of crepe paper and 15 more balloons for $6.05. This will be:

2x + 15y = 6.05 ......... ii

6x + 20y = 11.90 ......... i

2x + 15y = 6.05 ......... ii

Multiply equation i by 15

Multiply equation ii by 20

90x + 300y = 178.50 ........ iii

40x + 300y = 121 ........ iv

Subtract iv from iii

50x = 57.50

x = 57.50/50

x = 1.15

Therefore, a crepe paper cost $1.15

6 0

3 years ago

Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t

zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.

(a) How many different groups of 5 problems can be chosen from the 12

problems?

(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?

In (a)

Apply the formula

$\frac{n!}{(n-r)!(r!)}$

where n=12 and r=5

substitute values

$=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792$

In (b)

If Jerry did only 5 problems of one assignment then the probability will be

$\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}$

4 0

3 years ago

In circle O, AP = √10, PB = x and BC = 3. Find the value of x.

Artyom0805 [142]

Answer:

The value of x is $2\ units$

Step-by-step explanation:

we know that

Applying the tangent-secant theorem

$AP^{2}=PB*PC$

substitute the values and solve for x

$\sqrt{10}^{2}=x*(x+3)$

$10=x^{2}+3x$

$x^{2}+3x-10=0$

using a graphing tool

to solve the quadratic equation

The solution is $x=2\ units$

see the attached figure

7 0

4 years ago