True. The image of a translation is always congruent to the pre-image.
Proof: every point of the pre-image is move exactly the same distance and the same direction. That means that the shape stay the same but it is just located in a different place.
Hope this helps :)
Answer:
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Step-by-step explanation:
8m + 5n
8(3) + 5(- 5)
24 + (- 25)
24 - 25
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By pascal triangle this second term should be
5s^4v<span />
3:20 then 3:40 then 4:00 for both
30u^2v^3 and 8u^5v is : 2u^2v
