Answer:
W=2/(P-2L)
Step-by-step explanation:
Answer:
a)
AB is on the latitude 30°N.
<u>Find AB:</u>
- AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km
BC is along longitude 35°W
<u>Find BC:</u>
- BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km
<u>Total distance traveled:</u>
- 6482.15 + 5585.77 = 12067.92 km
<u>Convert the distance to nautical miles:</u>
12067.92/1.86 = 6488.13 nautical miles
b)
<u>Find the average speed:</u>
- 6488.13/22 = 294.92 nautical miles / hour
<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>
√27 = 5.2 (to 1 dp)
√39 = 6.2 (to 1 dp)
A. √39 is greater.
B. 6 is the only whole number between the two.
Hope this helped :)
Answer:
When we have something like:
![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
It is called the n-th root of x.
Where x is called the radicand, and n is called the index.
Then the term:
![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
is called the fourth root of 16.
And in this case, we can see that the index is 4, and the radicand is 16.
At the end, we have the question: what is the 4th root of 16?
this is:
![\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%20%5Csqrt%5B4%5D%7B4%2A4%7D%20%20%3D%20%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%20%3D%202)
The 4th root of 16 is equal to 2.
Answer:
Bruh?
Step-by-step explanation:
Bruh Bruh
