Answer:


Step-by-step explanation:
For this case we have the following data given:
2.3 3.1 2.8
1.7 0.9 4.0
2.1 1.2 3.6
0.2 2.4 3.2
Since the data are assumedn normally distributed we can find the standard deviation with the following formula:

And we need to find the mean first with the following formula:

And replacing we got:

And then we can calculate the deviation and we got:

Www. is your answer. Hope I could help
Answer:
The car uses less gas
They use the same amount of gas after
miles
Step-by-step explanation:
Given
The table represents the car mileage
--- The van
First, calculate the car's slope (m)

From the table, we have:

So, we have:



Calculate the equation using:



implies that for every mile traveled, the car uses 1/40 gallon of gas
Also:
--- The van
By comparison to: 

This implies that for every mile traveled, the van uses 1/5 gallon of gas.
By comparison:

This means that the car uses less gas
Solving (b): Distance traveled for them to use the same amount of gas.
We have:
--- The van
--- The car
Equate both

Collect like terms


Take LCM


Solve for -7x

Solve for x

Answer:
13.5
Step-by-step explanation:
150% × 9 =
(150 ÷ 100) × 9 =
(150 × 9) ÷ 100 =
1,350 ÷ 100 =
13.5
My proof :
If 150% × 9 = 13.5 =>
Divide 13.5 by 9...
... And see if we get as a result: 150%.