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3 years ago

If Kim has 10 apples and jack has 10 strawberries how many fruits do they have

Mathematics

1 answer:

Setler [38]3 years ago

6 0

Answer:10+10=20

20 apples plus 10 strawberries

Step-by-step explanation:

20 fruits in all.

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Find the approximate value of each trigonometric function.

vodka [1.7K]

Answer:

Given

tanθ = 3.454
θ is in the III quadrant

We know in the III quadrant both sine and cosine are negative.

Use the following identities to get values of sinθ and cos θ

sinθ = - tanθ/√(1 +tan²θ)
cosθ = - 1/√(1 +tan²θ)

Substitute the value of tanθ and find sine and cosine:

sinθ = - 3.454/√(1 + 3.454²) = - 0.961
cosθ = - 1/√(1 + 3.454²) = - 0.278

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3 years ago

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Why does -2^6 equal -64 but -2 x -2 x -2 x -2 x -2 x -2 equal 64? (The x's are multiplication)

NikAS [45]

Answer:

when there are no parentheses around the base, this being -2 we put parentheses around the the 2 and the exponent so it will look like -(2^6) making whatever answer you get negative.

when you put parentheses around the base (-2)^6 you will get 64

Step-by-step explanation:

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2 years ago

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What is the median of the data set?

Artist 52 [7]

Answer:

11.7

Step-by-step explanation:

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2 years ago

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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q^2+7q

viva [34]

Stay in school q^2*7q cuh

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2 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

2 years ago