Answer:
The position at time t is 
Step-by-step explanation:
From the question we are told that
The acceleration is 
The velocity at t = 0 is 
The position at time t = 0 is 
Generally acceleration is mathematically represented as

=> 
=> 
integrating both sides we have

=> 
Now at t = 0

=> 
So

Generally the position of the body is mathematically represented as

So

So

Now at t = 0

=> 
So

Answer:
Given that,
In right triangle ABC, C is the right angle.
sin A=0.4
To find cos B,
we get the triangle as,
we know that,
Hypotenuse of the triangle is AB
For the angle A, opposite side is CB
For the angle B, adjacent side is CB
From the definition of sine and cosine we get,

Also,

Comparing both we get,

It is given that sinA=0.4
Hence we get, cosB=0.4
Answer is: 0.4
Answer:
-290
Step-by-step explanation:
Just times -10 by 52
I can see why your confused, but the range of the function is <u>y≤−1 or y≥1</u> . The graph of the cotangent function looks like this: The domain of the function <u>y=cot(x)=cos(x)sin(x)</u> is all real numbers except the values where <u>sin(x)</u> is equal to 0 , that is, the values <u>πn for all integers n</u> .
<em>Hope this helps</em>
Have a great day!
<h3>-~- <u>WolfieWolfFromSketch</u> -~-</h3>