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2 years ago

Twice the sum of m and Five

Mathematics

1 answer:

REY [17]2 years ago

7 0

Answer:

2(m + 5)

Step-by-step explanation:

Twice means multiplication.

2 *

Sum means addition.

m + 5

2(m + 5)

Best of Luck!

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A garden is rectangular with an area of 6/7 square miles. If the length of the garden is 3/5 miles, what is its width?

Dafna11 [192]

Answer:

Step-by-step explanation:

Area= length x width

area=6/7, length=3/5, width=?

6/7=3/5 x width

6/7 divided by 3/5= 6/7 x 5/3 (you have to multiply by the recipricol, or flip the fraction.)

6/7 x 5/3=30/21= 1 3/7=width

7 0

3 years ago

5x + 3y=33 when y= 2x + 1

inn [45]

Hope that this helps.

3 0

3 years ago

A line passes through the point (-8,7) and has a

zaharov [31]

Answer:

y = (-5/2)x + 27

Step-by-step explanation:

Use the point slope formula y = mx + b.

Replace m with -5/2, x with -8 and y with 7:

7 = (-5/2)(8) + b. Find the y-intercept, b:

7 = -20 = b, or b = 27

The equation of this line is y = (-5/2)x + 27.

6 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

Furkat [3]

Answer:

x = -6 and x = 4

Step-by-step explanation:

In math, the critical points of a function are the points where the derivative equals zero.

So, first we will find the derivative of the function. The derivative is:

$f'(x)=3x^2 +6x-72$

Now, we are going to make the derivative equal zero and find the answers of the equation.

$3x^2 +6x-72=0\\3(x^2 +2x-24)=0\\3(x+6)(x-4)=0\\$

So we have that the critical points are the answers to this equation:

$x+6= 0 \\x= - 6$

and

$x-4=0\\x=4$

Thus, the critical points are x=-6 and x=4

8 0

3 years ago

The wind is blowing N 35.0 degrees W at 1.60 * 10^2 mph. A plane has an engine speed of 3.20 * 10^2 mph. Where should the pilot

andreyandreev [35.5K]

Answer: 24.2° SouthWest

Step-by-step explanation:

First step: DRAW A PICTURE of the vectors from head to tail (see image)

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

Perpendicular (x):

cos 35° = adjacent/hypotenuse

cos 35° = x/160

→ x = 160 cos 35°

Angle (θ):

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

θ = arcsin (160 cos 35°/320)

θ = 24.2°

Direction is down (south) and left (west)

7 0

3 years ago