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Tresset [83]
3 years ago
13

What is the circumference of a circle with a diameter of 190mm?

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

it's 502.6548246

Step-by-step explanation:

hhhhhhhg

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mylen [45]
1 is for circle
2 is for triangle
3 is for surface area
4 is for volume
5 0
3 years ago
What Force would be needed to extend a spring with a spring constant k=7 N/m that extends<br>0.3m?​
vladimir2022 [97]

Answer:

Force  =  - 2.1 Newton

Step-by-step explanation:

According to question ,

The value of Spring constant , K = 7  N/m   Newton per meter

And the spring is extended up to 0.3 meter

The Force experience on the spring is calculated from the Hook's Law

<u>The principal state that , the force applied on spring to extend or compress the spring to some distance is proportion to that distance. </u>

Let the force be F

So, F =  - K X

where K is spring constant and X is its displacement

Negative sign shows displacement of spring once it is stretched

And K is spring constant

So ,Force = ( - ) 7 × 0.3

I.e Force  =  - 2.1 Newton       Answer

4 0
3 years ago
What is the sales tax of a $178.90 video game system is the tax rate is 3.75%
juin [17]
It would be: 178.90 * 3.75%
= 178.90 * 0.0375
= 6.71

In short, Sales tax would be $6.71

Hope this helps!
3 0
3 years ago
Which expression is equivalent to:<br>15x + 20y <br>5(4x+3y) <br>5(3x+4y) <br>5y(3x + 4)​
alexandr402 [8]

Answer:

5(3x+4y)

Step-by-step explanation:

5 0
2 years ago
. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m
Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
2 years ago
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