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3 years ago

-7(2y+12)-6y=156 how am I supposed to solve this and figure out what hat “y” is?

Mathematics

1 answer:

Goryan [66]3 years ago

6 0

Answer:

y = -12

Explanation:

−7(2y + 12) − 6y = 156

Simplify both sides of the equation

−7(2y + 12) − 6y = 156

(−7)(2y) + (−7)(12) + −6y = 156 (Distribute)

−14y + −84 + −6y = 156

(−14y + −6y) + (−84) = 156 (Combine Like Terms)

−20y + −84 = 156

−20y − 84 = 156

Add 84 to both sides

−20y − 84 + 84 = 156 + 84

−20y = 240

Divide both sides by -20

-20y / -20 = 240 / -20

y = -12

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Show all work to write the expression in simplified rational exponent form:

tatyana61 [14]

Answer:

$x^{\frac{1}{2} } + 48$

Step-by-step explanation:

This is hard to explain, but basically you use exponent rules to switch it to an exponent

$(\sqrt[4]{x^{2} +4} )^{3}$

It's easiest if you calculate $4^{3}$ first

4³ = 4 x 4 x 4 = 48

Then convert the root to a fraction exponent

$\sqrt[4]{x^{2}} = x^{\frac{2}{4}} = x^{\frac{1}{2} }$

Combine them using addition, since addition was in the problem

$x^{\frac{1}{2} } + 48$

I hope this helps!

7 0

1 year ago

you are told that the sun pf another two whole numbers is 20 ans thair differnece is 15 is this possible

-Dominant- [34]

This is not possible if both numbers are whole numbers.

The larger number would be

(20+15)/2 = 17.5

The smaller number would be

(20-15)/2=2.5

So they cannot be whole numbers.

3 0

3 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago

Jonah’s restaurant bill comes to $25.65, and he leaves a 15% tip. What is Jonah’s total restaurant bill?

inessss [21]

Answer:

$29.50

Step-by-step explanation:

Not sure how your teacher wants you to round up.

$29.4975

Rounded -> $29.50

I'm assuming 2 decimal places; would be $29.50.

4 0

3 years ago

Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).

True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0

3 years ago