Answer: (5,8)
Step-by-step explanation:
So this is a matter of using a system of linear equations
To start if a total of 13 people got a ticket then we know that
x+y=13
x and y being explained in the problem
then if adult tickets are $40 and children tickets are $20 and the total cost is 360 we can set up the next equation
40x+20y=360
<em>If you were to plug in 1 lets say into x that means that 1 person bought a ticket for $40 this shown by 40 (1) this is the same premise for the childrens tickets.</em>
now we have
x+y=13
40x+20y=360
now we can solve by eliminating one of the variables this is done by either getting rid of the x or y and solving for the other. I solved for the y value first this looks like
-40(x+y=13)
40x+20y=360
Distribute the -40 to each value
giving you
-40x-40y=-520
40x+20y=360
add these together from the top down
the x's cancel leaving
-20y=-160
then isolate the y value by dividing both sides by -20
-20y/-20=-160/-20
leaving you with your y point
y=8
This is how many childrens rickets were sold now we can plug into the first linear equation
x+8=13
now easy subtration to isolate the x point
x+8-8=13-8
x=5
Finally leaving you with point (5,8)
Answer:
Numbers are 14 and 8
Step-by-step explanation:
Let the 2 numbers be x and y.
Write 2 equations:
x + y = 22
x - y = 6
Solve by substitution:
x - y = 6
x = y + 6
Plug into the other equation:
(y + 6) + y = 22
2y + 6 = 22
2y = 16
y = 8
Plug into either equation:
x + 8 = 22
x = 14
Numbers are 14 and 8
Answer:
312 $
Step-by-step explanation:
468 / 12 = 39 bags
8 x 39 = 312 $
so the answer is 312$
We have been given that :-
The length of a parasite in experiment A is ![2.5 \times 10^{-3}](https://tex.z-dn.net/?f=2.5%20%5Ctimes%2010%5E%7B-3%7D)
The length of a parasite in experiment B is ![1.25 \times 10^{-4}](https://tex.z-dn.net/?f=1.25%20%5Ctimes%2010%5E%7B-4%7D)
Let us write the the length of the parasite in experiment A in the exponent of -3.
![1.25 \times 10^{-4}= 0.125 \times 10^{-3}](https://tex.z-dn.net/?f=1.25%20%5Ctimes%2010%5E%7B-4%7D%3D%200.125%20%5Ctimes%2010%5E%7B-3%7D%20)
Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.
The difference in the length is given by
![2.5 \times 10^{-3} -0.125 \times 10^{-4}](https://tex.z-dn.net/?f=2.5%20%5Ctimes%2010%5E%7B-3%7D%20-0.125%20%5Ctimes%2010%5E%7B-4%7D)
![=2.375 \times 10^{-3}](https://tex.z-dn.net/?f=%3D2.375%20%5Ctimes%2010%5E%7B-3%7D)
Therefore, the length of the parasite in experiment A is
inches greater than the length of the parasite in experiment B.